All Questions
Tagged with lambda dictionary
513
questions
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31
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How can I sort a dictionary with in the dictionary by the keys of the second dictionary in python? [duplicate]
I have a dictionary as follows:
dict_1 ={'Spain':{'wins':1,'loses':0,'draws':2,'goal_difference':2, 'points':3},'Portugal':{'wins':3,'loses:1,'draws':1,'goal_difference':0,'points':4},'Morocco':{'wins'...
0
votes
1
answer
53
views
Iteratively source a value from a dictionary
I have a data set where I know a limited number of values and based on other values in a data set I can figure out what the subsequent values are. I could do this with a huge if function, but I know ...
- 587
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0
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35
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How to convert json string into json object of list if you are working with list of dictionary in c# lambda function using newtonso
I am working on a lambda api, and i need to get response in object of list.
here is my model:
public class Response
{
public List<Dictionary<string, string>> FailedTenant { get; set; }
...
0
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22
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lambda function in key argument in sorted() method in python? [duplicate]
I found this code from online and tries to find what is the logic.But i didn't get it.
from collections import Counter
arr = [4,3,1,1,3,3,2]
k = 3
c = Counter(arr)
print(c)
s = sorted(arr,key = lambda ...
0
votes
1
answer
28
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Create dataframe columns from a dictionary using lambda expression
I would like to create a pyspark dataframe dynamically using lambda form a give dictionary. Below is my dictionary.
cols = [
{'Technical Label':'UserID', 'Column Mapping':'UID','Technical Column':'No'}...
- 2,075
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33
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Python: when lambda is used to iterate, notation does not make sense [duplicate]
Here is some code from Python Cookbook.
portfolio = [
{'name': 'IBM', 'shares': 100, 'price': 91.1},
{'name': 'AAPL', 'shares': 50, 'price': 543.22},
{'name': 'FB', 'shares': 200, ...
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2
answers
83
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Using counter in map, lambda in Python
I need to create this list ["1", "12", "123", "1234", "12345", ..., "123456789"] without using loops. How can I do it by using map, lambda ...
- 23
0
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63
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Using reduce and lambda function to find average grade in a dictionary list
In a dictionary list containing student information like name, age, grade. Use lambda and reduce function to find average grade of all students?
I am not able to use the lambda and reduce function to ...
0
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0
answers
11
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Using lambda function to sort dictionary list
A dictionary contains name and age of a person. Use lambda function to filter out dictionaries for age less than 30 and then print the names of person in sorted list with name capitalized and prefixed ...
0
votes
1
answer
16
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How to sort a dictionary inside a dictionary by values?
I am trying to sort this dictionary that contains divisions of hockey teams. Each team is an element of the dictionary and each team's value is a dictionary that has a number of points (PTS) and a VRP ...
0
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0
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76
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How to add an x before each element in a list of strings so I can use it then in a lambda expression
I have the code I show below, where I make a dictionary after grouping by some columns. My goal is to transfer the mean I've calculated in the groupby dataframe to an other dataframe. For that I've ...
0
votes
1
answer
146
views
How to convert a List<String> to Map<String, Long> using Lambda, where the key is the String and the value is a count of the number of vowels?
Given:
List<String> myStrings = Arrays.asList("broom", "monsoon");
Return:
Map<String, Long> stringToNumberOfVowels = Map.of("broom", 2, "monsoon", ...
- 155
-2
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1
answer
37
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error in dictionary , could not find why i cannot add c [closed]
from collections import defaultdict
# Defining the dict and passing
# lambda as default_factory argument
d = defaultdict(lambda c: "Not Present")
d["a"] = 1
d["b"] =...
0
votes
1
answer
75
views
defaultdict with a lambda that uses the key as a parameter [duplicate]
I was trying to create a defaultdict where the key was used as a parameter to create a classed object, but I get a TypeError when I try. I've put a minimum example below
from collections import ...
- 759
0
votes
1
answer
22
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Get the key of the value satisfied the conditions in the dictionary
I have a dictionary as follows :
k = {'e': 8, 'f': 2, 'g': 3}
I want to give the condition: the value is smaller than the 5:
(For example: value < 5)
at the result:
the key of the max value under ...
- 33