103

Does anyone an idea how to rewrite following SQL query to generate results, that would contains only one occurrence of name? (results grouped by user).

The query

SELECT array_to_string(array_agg(CONCAT(u.firstname, ' ', u.lastname)), ', ')
FROM log_has_item logitem
  INNER JOIN log log ON log.id = logitem.log_id
  INNER JOIN worker u ON log.worker_id = u.id
WHERE logitem.company_id = 1

Executable query is avaiable on sqlfiddle.com. Click on Run SQL button and you will result, which contains Frantisek Smith twice

8
  • 9
    array_agg(distinct concat(...)))
    – user330315
    Commented Oct 14, 2014 at 14:49
  • In postgre 9.0+ there is string_agg(text,text) function. It may be easier to write string_agg(CONCAT(...),', ') Commented Oct 14, 2014 at 15:30
  • @a_horse_with_no_name distinct works fine, but scrambles the order. Any way to preserve it?
    – Rodrigo
    Commented Mar 3, 2016 at 13:57
  • @Rodrigo: use an order by inside string_agg()
    – user330315
    Commented Mar 3, 2016 at 13:58
  • @a_horse_with_no_name I tried string_agg(distinct nome order by l.id,', ') and string_agg(distinct nome order by nome,', '), but both give "function string_agg(character varying) does not exist". I'll ask a question with the full sql to show you.
    – Rodrigo
    Commented Mar 3, 2016 at 14:00

2 Answers 2

176

You can use the distinct keyword inside array_agg:

SELECT ARRAY_TO_STRING(ARRAY_AGG(DISTINCT CONCAT(u.firstname, ' ', u.lastname)), ', ')
FROM log_has_item logitem
  INNER JOIN log log ON log.id = logitem.log_id
  INNER JOIN worker u ON log.worker_id = u.id
WHERE logitem.company_id = 1

SQLFiddle with this example

4
  • 6
    Any way to preserve the order using distinct?
    – Rodrigo
    Commented Mar 3, 2016 at 13:57
  • 4
    ERROR: DISTINCT is not implemented for window functions SQL State :0A000 (PostgreSQL 9.5.5)
    – P01550n
    Commented Dec 5, 2016 at 13:57
  • 2
    Saved me from having to write my own aggregate function!
    – thalisk
    Commented Oct 14, 2017 at 11:58
  • 1
    Wouldn't STRING_AGG be better? See my answer.
    – Vérace
    Commented Nov 1, 2021 at 9:27
6

No need to go all round the houses with ARRAY_TO_STRING(ARRAY_AGG( when a simple STRING_AGG will do as follows (code available on the fiddle here):

--
-- Simplified
--

SELECT
  DISTINCT
  STRING_AGG
  (
    DISTINCT CONCAT(w.firstname, ' ', w.lastname), ', '
  ) AS "The workers"
FROM log_item li
INNER JOIN log l ON li.log_id = l.id 
INNER JOIN worker w ON l.worker_id = w.id
WHERE li.company_id = 1;

Result:

                The workers
Frantisek Smith, Peter Duff

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